In 1980 median family income was about$16,000, and in 2000 it was bout $40,000. (a) find the slope of the line passing through points 1980,16000 and (2000,40000). (b) Interpret the slope rate of change. (c) If this trend continues, estimate the median family income in 2006
Do you know the formula for slope?
let y2-y1 over x2-y2
and divide by 3
\[M=y _{2}-y_{1}/x_{2}-x_{1}\]
yes
Alright, your two points are (1980, 16000) and (2000, 40000) whats the slope?
the slope do i subtract 40,000 from 16,000
and divide by 3
No there is no dividing by 3, use the slope formula
well you have to subtract the two top numbers and the instructions says divide by 3
i am going to look again to see what two numbers for the slope
You do 40000-16000/2000-1980
ok i got to calculate
24,000/20
Which is 1200
yes i got that too
Alright do you know how to do point-slope form?
i believe the family rate decreases by 12,000 between 1980-2000
No, the median family income increased by 24000 between 1980 and 2000. When it says to interpret the slope that means to say what it means in the context of this problem. It means every year the median income increases by $1200
oh ok i see so the family income of 12,000 will increase in 2006
silly me thank you
Wait, for part c we have to do something else
ok
this is the formula we use to get an equation that we can use to estimate the income in 2006. \[y-y _{1}=m(x-x _{1})\]
SO WEHAVE TO FIND THE FAMILY INCOME FOR 2006
So which point do you want to use to plug into the formula
SO THE M=12000 ON HERE?
no 1,200. you added a 0
Do you want to use the point (1980, 16000)?
16,000-12,000
when we plug everything in, itll look like y-16000=1200(x-1980)
Y-16000=12000X-23760000 i think this is wrong but i multiplied12000 into whats in the brackets
No thats what you do first, but you keep adding a 0. the slope is 1,200, not 12,000
y-16000=1200x-237600
You keep forgetting or adding zeros. y-16000=1200x-2376000
ok well i think im not getting this second part
You have the right idea you just keep adding or forgetting zeros. after we get that we subtract 16000 from both sides
ok subtract 16000 and after i divide
Im sorry, add 16000, not subtract. you end up with: y=1200x-2360000
where x stands for the year and y stands for the median income. What would you plug in for x since you want to find the income for 2006?
oh ok add 16000 because it is already a negative so change to add
Yep so if you want to find the income for 2006, what do you plug in for x?
y=1200(20)-2360000
2000-1980=20
x=20
No, x represents the year, if you want to find the income for 2006, you plug in 2006 for x. y=1200(2006)-2360000
ok i calculate now for answer
47,200
Thats correct
omg this is hard
Well now you're all done =D
thanks i guess its hard with my infant aggravating me thank u
Join our real-time social learning platform and learn together with your friends!