Graph 3x-4y=12 using the slope and y-intercept. How do I do this?
First isolate y on the left side of the equation.
So we have it in standard form
Sorry, math is one of my weakest subjects. I don't really understand it at all.
Well the standard form is y=mx+b where m is the slope and b is the y interecept, so if we get it in that form we can graph it the way the question asks. To get y by itself on the left, start by subtracting 3x from both sides so you get: -4y=-3x+12 can you think of what we should do next?
The slope would be -3 and the y-intercept is 12 if I remember correctly.
Well we havent gotten y all by itself just yet, i was asking what we could do next in order to do that
Subtract the -3x
We did that and got -4y=-3x+12 How would we get rid of the -4 in front of the y?
Divide.
Yep, and what do you get?
y=\[ 3(-x+4) \over4\]
Just divide each one by -4 y=3/4x-3
So whats the slope and the y intercept?
Slope would be 3/4 and the y-intercept would be 3
y intercept would be -3, dont forget negatives
Right.
So you would plot a point at the y intercept (0, -3) and then use rise over run to find the next point and draw a straight line through them
3/4 would be up 3 right 4
Alright, thanks. I don't know why I can't get these.
You're welcome. Just practice with different ones and you'll get the hang of it.
I'll remember that. :)
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