Question

Factor 8x^2-10xy-3y^2

Answer 1

So what is the curriculum? What course is this?

Answer 2

Is there a particular method that you must use? Are you not allowed to use the quadratic formula?

Answer 3

what's the problem?

Answer 4

factor the trinomial 8x^2-10xy-3y^2

Answer 5

Consider this: \[ax^2+bx+c\]Where \[a=8,b=-10y, c=-3y^2\]

Answer 6

Ok what would be the next steps

Answer 7

multiply 8 and 3?

Answer 8

\[\Large x = \frac{-b\pm \sqrt{ b^2-4ac }}{2a}\]

Answer 9

That is the quadratic formula.
You could also try splitting the middle.

Answer 10

that is what i am learning quadratic

Answer 11

Okay, so solve for \(x\) in terms of \(y\) using the quadratic formula. Do that first.

Answer 12

my answer is (2x+y)(4x-3)

Answer 13

correct?

Answer 14

Nope, it's not correct.

Answer 15

(2x-3)(4x+y) ??

Answer 16

Almost.

Answer 17

where am I messing up at?

Answer 18

Simplifying
8x2 + -10xy + -3y2

Reorder the terms:
-10xy + 8x2 + -3y2

Factor a trinomial.
(2x + -3y)(4x + y)

Final result:
(2x + -3y)(4x + y)

Answer 19

You're missing a y for the first factor.

Answer 20

I dont get where the Y would come from. it was not a GCF

Answer 21

8x^2 = (4x)(2x)
-3y^2 = (-3y)(y)

Answer 22

8x^2-10xy-3y^2
= 8x^2 - 12xy + 2xy -3y^2
= 8x^2 + 2xy - 12xy -3y^2
= 2x ( 4x + y) - 3y (4x+y)
= ...

Answer 23

Does that help?

Answer 24

yes thanks

Answer 25

You're welcome. Hope that you understand where the y comes from.