Solve 2 cot^2 x - cot x = 3 at interval (0, 2pi)
Move the 3 to the other side, then replace COT X with something simple.. like U. And then look at it, and think back to algebra, how you would solve a problem like that.
Let y = cot x. Substitution! Solve for y from the quadratic formula and then put that back into y = cot x.
@zepdrix , multiply the other side by 3?
subtract 3 from both sides :D
If you use what zepdrix and I are saying, you will get: \[ 2y^2 - y - 3 = 0. \]Once you solve for that. You can find the arccot of that, to get your answer.
@Ahaanomegas, using the quadratic formula?
Yes, use quadrant formula.
I got 3/2 and -1
Well, I got x = \[x = \tan^{-1} \frac{4}{1 \pm 5} = 33.69º \text{ and }\frac{3 \pi}{4}\]
Correction: Quadratic formula. Not quadrant. ;)
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