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Find the limit as x approaches negative infinity. (3x-4)/(sqrt(2x^2 - 5))
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Maybe try L'Hopital's Rule: differentiate top and bottom?
Looks like you'll have to do that twice if you're going to try that.
Sorry, my teacher hasn't taught us L'Hopital's Rule so I don't know where to begin.
What other methods have you learned to evaluate limits? You notice that if you plug in x=∞ you get the indeterminate form ∞/∞?
ohhh i see, i see. So since infinity/infinity = 1, then the answer would be -3/sqrt of 2?
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That's usually how I think about it (and it works, that is the correct answer), but stricter mathematicians wouldn't like that.
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