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Mathematics 10 Online
OpenStudy (anonymous):

Integral by hand

OpenStudy (anonymous):

\[\int\limits_{0}^{3}\frac{ dx }{5x+1 }\]

OpenStudy (wasiqss):

aplly Ln

OpenStudy (wasiqss):

because derivative of function is present in numerator

OpenStudy (anonymous):

how do i do that?

OpenStudy (anonymous):

\[\int_{x_1}^{x_2} \frac{1}{ax+b} = [\frac{1}{a} \ln |ax+b| ]_{x_1}^{x_2}\]

OpenStudy (anonymous):

Oh... I missed a dx over there..

OpenStudy (anonymous):

how did you know that? is it a rule?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

so i cant use that because if the dx?

OpenStudy (anonymous):

Eh.. I meant \[\int_{x_1}^{x_2} \frac{1}{ax+b} dx= [\frac{1}{a} \ln |ax+b| ]_{x_1}^{x_2}\] I missed the dx in the previous comment.

OpenStudy (anonymous):

It's a more general case of \[\int\limits \frac{1}{x}dx = \ln|x|+C\]

OpenStudy (anonymous):

So is this right? \[\frac{ 4\ln(2) }{5 }\]

OpenStudy (anonymous):

Yep, that works.

OpenStudy (anonymous):

thanks

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