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Mathematics
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Integral by hand
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\[\int\limits_{0}^{3}\frac{ dx }{5x+1 }\]
aplly Ln
because derivative of function is present in numerator
how do i do that?
\[\int_{x_1}^{x_2} \frac{1}{ax+b} = [\frac{1}{a} \ln |ax+b| ]_{x_1}^{x_2}\]
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Oh... I missed a dx over there..
how did you know that? is it a rule?
Yes.
so i cant use that because if the dx?
Eh.. I meant \[\int_{x_1}^{x_2} \frac{1}{ax+b} dx= [\frac{1}{a} \ln |ax+b| ]_{x_1}^{x_2}\] I missed the dx in the previous comment.
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It's a more general case of \[\int\limits \frac{1}{x}dx = \ln|x|+C\]
So is this right? \[\frac{ 4\ln(2) }{5 }\]
Yep, that works.
thanks
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