To launch a communication satellite in a circular orbit 1000 km above the surface of the Earth, what orbital speed must be imparted to the satellite? Find the acceleration due to gravity at the orbit.
equate a(due to g) to a=v^2/r a(due to g)=F(g)/m=|-GMm/r^2 x (1/m)| =GM/r^2 so v^2/r=GM/r^2, by this you can find velocity b/c r is known, and both the mass of Earth and the gravitational constants are known. Then you find the acceleration by plugging your velocity back to the equation a=v^2/r
is r=1000km? @lailaiwd
nope, you need to add the radius of Earth to 1000km
to get r?
I believe so. This is a common problem, and you can probably find similar solutions on Google.
thanks a lot!! x
definitely :D is that your picture? If so, you're pretty
haha..yes it is... i get that doubt a lot!! lol
v=5.98 x 10^24 m/s? a=2.20 m/s^2? @lailaiwd
sorry... i'm not in the condition to to the numerics myself... it's almost 3 am, and I'm dozing
its ok...maybe you should try get some sleep...
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