evaluate following piecewise defined function @ x=-3,x=1/4, and x=3
f(x)3^rt9x for x<0
8x for 01/2
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OpenStudy (anonymous):
wow am I lost...
OpenStudy (campbell_st):
ok... so you have 3 functions with differing domains.
I am unsure of the 1st function but you need to substitute x = -3 as x<0
next you need to find
f(1/4) so you use f(x) = 8x since 0<= x <= 1/2
and lastly
f(3) so you use 2/3 x since x>1/2
OpenStudy (anonymous):
???
OpenStudy (campbell_st):
so you can't find
f(1/4) when f(x) = 8x?
OpenStudy (anonymous):
2
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OpenStudy (campbell_st):
thats good
now f(3) uses the last function f(x) = 2/3 x becuase x > 1/2
can you now find f(3)
OpenStudy (anonymous):
2
OpenStudy (campbell_st):
ok... so the conditions to the right of each function, determine which to use...
now for x = -3
you need to find f(-3) which uses the 1st function, that I can't understand, because x < 0
OpenStudy (anonymous):
=-3
OpenStudy (campbell_st):
well looks like you have a solution. hope it helps
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OpenStudy (anonymous):
f(x)=\[\sqrt[3]{9x}\]
OpenStudy (anonymous):
that is the 1st one. But what do I do with these numbers