Question

How to resolve it into partial fractions:
\[\frac{1}{(u^2-1)^2}\]

Answer 1

note that\[\frac{1}{(u^2-1)^2}=\frac{1}{(u-1)^2(u+1)^2}\]

Answer 2

Yes... But how to continue?

Answer 3

substitute 1 by 1/4((u+1)-(u-1))^2

Answer 4

open the bracket cancel the terms and then u will get it simplified...

Answer 5

@RolyPoly

Answer 6

How can you think of this term: 1/4((u+1)-(u-1))^2 ?

Answer 7

mathematical logic
u just have to substitiue it in such a way that the denominator cancels out and u get ur task done...
u will have to think it ..
no formula for it..

Answer 8

Hmm.. even though I don't get this ''mathematical logic'', but thanks still! I think I can work that partial fraction out from your hint!