Solve the system by graphing.
just change the equations into standard form
then graph it on your calculater
@andriod09 could you help me in this math problem please!
first thing is first. make the equations on the same side. \[(-2x)=2y-4\] \[2x-y=-(5)\]
how do I do that?
just flip it around? so -2x = 2y - 4 2x = y - 5
After you help me with this question could you help swiftskier96 ?
yea. you need to put either a variable on the left side \[(here=)\] or on the right side with the\[=(here)\]
So just like I did?
yea. now, do you know how to add equations?
yea 4x = 3y +1 IS this right?
idk let's see: \[-2x = 2y - 4\] \[2x = y - 5\] \[0=3y-9\]
yea I messed but now I know :)
the -2x and the 2x cancel each other, which, in tern, leaves 0 in its place, and then you add the 2y and the y, and then the negatives.
yea I just did it the wrong way I only got 3y correct :o
now to graph it, you use the equation: \[y=mx+b\] \[0=3y+(-9)\]
I don't know how I would graph this?
then it would be: \[\frac{ \Delta y} {\Delta x}\] = \[\frac{\Delta (3y} {\Delta 0}\] and you would start at -9 on the graph on the y axis.
Did you check out the multiple choice answers I put up on here too?
none of em start with the -9 on the graph on the y axis
Its the first one. sorry, got mixed up.
oh the first one is the answer? Alright! Thanks!!! Could you help another girl its similar to this problem
if you link it to me.
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