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Mathematics 10 Online
OpenStudy (anonymous):

Solve the system by graphing.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

just change the equations into standard form

OpenStudy (anonymous):

then graph it on your calculater

OpenStudy (anonymous):

@andriod09 could you help me in this math problem please!

OpenStudy (andriod09):

first thing is first. make the equations on the same side. \[(-2x)=2y-4\] \[2x-y=-(5)\]

OpenStudy (anonymous):

how do I do that?

OpenStudy (anonymous):

just flip it around? so -2x = 2y - 4 2x = y - 5

OpenStudy (anonymous):

After you help me with this question could you help swiftskier96 ?

OpenStudy (andriod09):

yea. you need to put either a variable on the left side \[(here=)\] or on the right side with the\[=(here)\]

OpenStudy (anonymous):

So just like I did?

OpenStudy (andriod09):

yea. now, do you know how to add equations?

OpenStudy (anonymous):

yea 4x = 3y +1 IS this right?

OpenStudy (andriod09):

idk let's see: \[-2x = 2y - 4\] \[2x = y - 5\] \[0=3y-9\]

OpenStudy (anonymous):

yea I messed but now I know :)

OpenStudy (andriod09):

the -2x and the 2x cancel each other, which, in tern, leaves 0 in its place, and then you add the 2y and the y, and then the negatives.

OpenStudy (anonymous):

yea I just did it the wrong way I only got 3y correct :o

OpenStudy (andriod09):

now to graph it, you use the equation: \[y=mx+b\] \[0=3y+(-9)\]

OpenStudy (anonymous):

I don't know how I would graph this?

OpenStudy (andriod09):

then it would be: \[\frac{ \Delta y} {\Delta x}\] = \[\frac{\Delta (3y} {\Delta 0}\] and you would start at -9 on the graph on the y axis.

OpenStudy (anonymous):

Did you check out the multiple choice answers I put up on here too?

OpenStudy (anonymous):

none of em start with the -9 on the graph on the y axis

OpenStudy (andriod09):

Its the first one. sorry, got mixed up.

OpenStudy (anonymous):

oh the first one is the answer? Alright! Thanks!!! Could you help another girl its similar to this problem

OpenStudy (andriod09):

if you link it to me.

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