Question

use the elimination method to solve the following system of equations.

Answer 1

5x – 9y = –16
2x + 6y = –16

Answer 2

5x – 9y = –16-(1)
2x + 6y = –16-(2)
Multiply (1) by 2 and u will get
(1)*2=>10x-18y=-32-(3)
Multiply (2) by 3 and u will get
(2)*3=>6x+18y=-48-(4)
Nw can u tell me vat u get when u add (3) and (4) @evergirl?

Answer 3

thank u!

Answer 4

yw:)
Can u continue after that?

Answer 5

I'll try

Answer 6

ha k:)

Answer 7

x—2 equations combined:
5x - 9y = 2x + 6y
3x = 15y
x = 5y

y—1st equation:
5(5y) - 9y = - 16
25y - 9y = - 16
16y = - 16
y = - 1

x—2 equations combined:
= 5(- 1)
= - 5

Answer: x = - 5, y = - 1

Answer 8

Ur answer is perfect:)
The method u hav used is substitution method bt they want u to do it in elimination method

Answer 9

oh ok

Answer 10

how about this.........First, multiply the second equation by 2.5:

5x + 15y = -40

Now, subtract equation 2 from equation 1:

5x - 9y = -16
- 5x + 15y = -40

-24y = 24

Dividing by -24:

y = -1

Now we can just plug this into either of the equations and solve for x:

5x - 9(-1) = -16
5x = -16 - 9
5x = -25
x = -5

x = -5
y = -1

Answer 11

When u subtract equation 2 from equation 1 u get
5x - 9y = -16
- 5x + 15y = -40
10x-24y=24

Answer 12

thanks

Answer 13

u can eliminate x terms by adding eqn1 and eqn 2

Answer 14

5x - 9y = -16-(1)
- 5x + 15y = -40-(2)