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Mathematics 20 Online
OpenStudy (anonymous):

Linear Algebra question. Find the inverse of the following n x n matrix (see diagram to follow).

OpenStudy (anonymous):

|dw:1349105226399:dw| Those are spaces between the + and the - signs, it is not a vector (don't add them up), it is an n x n matrix.

OpenStudy (phi):

does this say the 1st row is all +1 the 2nd row starts with -1, then all +1 and the -1 moves in one step each row down?

OpenStudy (anonymous):

yes, It's hard to "draw" that with the drawing tool.

OpenStudy (anonymous):

I'm working on it here myself, and I think I see a pattern developing. You don't have to continue working on it if you don't want to. I think I can get it now. It will just take me a little time.

OpenStudy (phi):

I just finished verifying it... I don't like posting bogus answers after factoring out 1/2 I see a n-1 x n-1 diagonal submatrix with -1 on the diagonal 1's along the left and bottom, except for the n,1 position which has 3-n at least for n≥3

OpenStudy (phi):

works for n≥2

OpenStudy (anonymous):

I think I've got it. The first row is 1/2, -1/2, 0, 0, ... 0. The second row is 1, 0, -1, 0, ... 0. The third row is1, 0, 0, -1, ... 0. The (n-1)th row is 1, 0, 0, 0, ... -1. The nth row looks like (3-n)/2, 1, 1, 1, ... 1. The tricky part for me was I saw what I thought was a slighty different pattern which was throwing me off at first. Part of the trick also was the 0's. I verified this matrix and it seems to work fine.

OpenStudy (phi):

this is 2 * the inverse for a 5 x 5 1 -1 0 0 0 1 0 -1 0 0 1 0 0 -1 0 1 0 0 0 -1 -2 1 1 1 1

OpenStudy (anonymous):

Sorry, last row has my 1's replaced with 1/2.

OpenStudy (anonymous):

It looks like we both have the same answer, just written a little differently.

OpenStudy (phi):

all the entries should be 1/2, -1/2 or 0 except the bottom left

OpenStudy (phi):

but you say The third row is 1, 0, 0, -1, ... 0. that should be 1/2 0 0 -1/2 ... 0 unless you factored out the 1/2

OpenStudy (anonymous):

Yes, both you and I got the same answer, and I also verified it, and it works. The (3-n)/2 was a little tricky but not really that bad once I got started. Thanks for coming up with the same (correct) answer. Have a good day. I'm going to consider this question closed now. You get a medal.

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