Graph the equation y=-3/4 x-3
when you look at an equation like this, it is in the format of a line equation. y = mx + b <<--- where the "m" in front of the x is the slope <<--- and the "b" at the end is where the line crosses the y-axis, or it's "y-intercept"
So, draw your x and y axis, and find the place on the y-axis corresponding to that "b" term in your example, and that is one point. Then extend the line in both directions using the slope, where slope is "rise over run".
|dw:1349109643596:dw| so it would look like this.
almost... It crosses the y axis at b = -3, not b = 3. So it would be that same graph shifted down below the y axis... same slope, but crossing at (0, -3)
Ohhh! okay. thank you so much
glad to help :)
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