-5x+y-4z=60
2x+4y+3z=-12
6x-3y-2z=-52
solving a 3 variable linear system
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OpenStudy (andriod09):
wow. all you have to do is add them i believe.
OpenStudy (anonymous):
well my math teacher said to use elimination using two different sets of the 3 so i did but i got z as a decimal and he said all the variables were whole numbers so idk what to do
OpenStudy (andriod09):
add 2 of them, so you cab get the better of the 2, then you substitute the vaiable in the last equation.
OpenStudy (anonymous):
okay ill try, thanks
OpenStudy (anonymous):
@kirstenande this was along question!!!
i got:::
x=-8
y=4
z=-4
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OpenStudy (andriod09):
greek, it should be y=5 not 4.
OpenStudy (anonymous):
@andriod09 substitute all of my values back into one of the 3 eqns.... LHS=RHS
OpenStudy (anonymous):
@kirstenande U getting it???
OpenStudy (andriod09):
ohhh fail.
OpenStudy (anonymous):
@andriod09 :P
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OpenStudy (anonymous):
i just re did it and when i got it down to the two equations with two variables i got
22x+19z=-252
-9x-14z=128
OpenStudy (anonymous):
i just re did it and when i got it down to the two equations with two variables i got
22x+19z=-252
-9x-14z=128