integrate 3+5t dt, find the C also
The gas piston of an M4 carbine rifle with in initial position of x0=5[mm].experiences a velocity defined by x’=3+5t for one second. What is the piston’s finale position?
Are we using the definition of an integral, or are we just taking an anti derivative?
Okay so do you know how to find the indefinite integral here? \[\int 3+5t\ dt\]
of course it will be 3t+5t square/2 + c, not the point is how to find the C
did you ready the question plz help me.
The gas piston of an M4 carbine rifle with in initial position of x0=5[mm].experiences a velocity defined by x’=3+5t for one second. What is the piston’s finale position?
Okay, so we know that \[5 = 3(0)+5(0)^2+c\]Can you solve for c?
C will be 5
So you have the function of position with respect to time. They gave you a time.
So what is the final position, please write the full step
the time is in one secant
\[3(1)+5(1)^2+5\]Right?
yes
My Dear thanks for helping me please once again ready the question and write, the step and final anwer
I mean read the question sorry by mistake it wrote ready
you mean the final answer is 13 mm
Yeah....
I am studying dynamics of structure that is why
how you find 5=3(0)+5(0)2+c, zero in here where zero come from 0
We let \(t=0\) at the initial time. And \(t=1\) at the final time.
Hey wio thanks alot i got the answer but i need the steps
please write from start to end
To find c, you need a sample point. They point they gave you is (0,5).
" initial position of x0=5[mm]" means (0,5)
then
suppose someone gave you this question
The gas piston of an M4 carbine rifle with in initial position of x0=5[mm].experiences a velocity defined by x’=3+5t for one second. What is the piston’s finale position?
from where you start the solution
hey anyone plz help me
see we integrate 3+5t dt = 3t+5t square / 2 + c
how to find C
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