Question

6 messages outs of 40 need to be corrected. What is the probability that 38-40 messages need to be corrected out of 200?

Answer 1

as in either 38,39 or 40 our of 200?

Answer 2

*out of 200?

Answer 3

if i read the question correctly you have to compute
\[P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}\] for
\[k=38,k=39,k=40\] with \[p=\frac{3}{20}, 1-p=\frac{17}{20}\] and \[n=200\]

Answer 4

THanks, yea out of 200 messages what is the probability that between 38-40 messages will need to be corrected :)

Answer 5

then it is the computation i wrote above. compute each, then add them

Answer 6

Ok, Awesome thanks!

Answer 7

I'm a little confused with the (1-p)^n-k

Answer 8

Seems like that would be to the ^160 power??