Question

Help please!

Indicate the equation of the given line in standard form.

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

Answer 1

can u find midpoint of R and S ?

Answer 2

I'm not sure how to.

Answer 3

mid-point of (x1,y1) and (x2,y2)
is
x= (x1+x2)/2
y= (y1+y2)/2

Answer 4

What do I do after that?

Answer 5

what is the mid-point u get ?

Answer 6

2.5, 5

Answer 7

5-1=4
4/2=2
6+5=11
11/2=5.5
so the midpoint is
(2,5.5)
ok?

Answer 8

Oh, gotcha. Sorry, I read that backwards in my head. Haha what do I do after that, to get the equation of the line?

Answer 9

now find the slope of given line:
The slope of the line through points (x1,y1) and (x2,y2) is given by :
\(\huge m=\frac{y_1-y_2}{x_1-x_2}\)
now,just put the values and find m.

Answer 10

I got - 1/7

Answer 11

how ?

Answer 12

6 - 5 = 1
-1 - 5 = -6

I typed 7 by mistake instead of 6.

Answer 13

so its -1/6
then slope of perpendicular will be reciprocal inverse.
so it'll be m=6
now you have slope and point (2,5.5)
can u find the equation of that line ?

Answer 14

y-2=6(x-5.5) ?

Answer 15

u reversed the points.
y-y1=m(x-x1)
y-5.5 = 6(x-2)

Answer 16

Got it. Thanks!

Answer 17

welcome ^_^