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Find the limit as x approaches 0 [(1/square root of 1+x)-1]/x
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\[\lim_{x \rightarrow 0} \frac{ \frac{ 1 }{ \sqrt{1+x} }-1 }{ x }\] Hmm looks like this?
Yes it does
What have you tried so far? There are a couple approaches, you can get a common denominator in the top, then multiply top/bottom by the CONJUGATE of the top. Or alternatively, you could multiply the top/bottom by the conjugate of the top right now, but it might be a little messy doing it that way :D
Still confused lills? Need to see the steps? :o
I started with timesing by radical 1+x but I got confused after that
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|dw:1349137122447:dw| Were you able to get to here ok? :D
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