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Integrate (sqrt(1 + x^2)/x)
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\[x = \tan \theta dx = \sec^2 \theta \]
I think I need a simpler route with the trig substitution.... the way I tried was lasting almost two pages....
yes, that substitution is correct, so what did u get in terms of theta ?
It's the substituting it into the equation, then simplifying that I experienced trouble with.
1+tan^2 theta = ? sec theta* coas theta = ?
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*cos
u get sec theta * sec^2 theta / tan theta , right ?
yeah
so what is sec theta / tan theta ?? and write sec^2 theta as 1+ tan^2 theta
u will get , csc t (1+sec^2 t) = csc t +csc t .sec^2 t =csc t+ tan t sec t integrate these seperately, these are standard integrals. then resubstitute for t
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