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Mathematics 15 Online
OpenStudy (anonymous):

quick integral question!

OpenStudy (anonymous):

Question: \[\int\limits_{?}^{?}\frac{ 2 }{ x ^{2}+6x+11 }dx\]

OpenStudy (anonymous):

My Approach:

OpenStudy (anonymous):

\[\int\limits_{?}^{?}\frac{ 2 }{ (x ^{2}+6x+9)+2 }\]

OpenStudy (anonymous):

those are question marks on the limits right? they are not 2s are they?

OpenStudy (anonymous):

\[\int\limits_{}^{}\frac{ 2 }{ (x+3)^{2}+2}dx\]

OpenStudy (anonymous):

Let u = x + 3 \[\frac{ du }{ dx } = 1\] \[du = dx\]

OpenStudy (anonymous):

Sub u into integral \[\int\limits_{}^{}\frac{ 2 }{ u ^{2}+2}du\]

OpenStudy (anonymous):

Then I'm not sure where to go from there...got any ideas?

OpenStudy (anonymous):

you probably need to use trig substituion

OpenStudy (anonymous):

I can't seem figure out a trig substitution that would fit...:/

OpenStudy (anonymous):

ah \[\int\limits_{}^{}\frac{ 2 }{ u ^{2}+\sqrt{2}^{2} }du\]

OpenStudy (anonymous):

Still looks hairy though with that sqrt 2

OpenStudy (turingtest):

it's really not so bad\[u=\sqrt 2\tan\theta\]\[\int\frac{2\sqrt2\sec^2\theta d\theta}{2\tan^2\theta+2}=\sqrt2\int\frac{\sec^2\theta d\theta}{\tan^2\theta+1}\]

OpenStudy (anonymous):

then do I apply trig substitution?

OpenStudy (anonymous):

why not just use the integral formulas? first page, second to the last of the formulas for common integrals..... http://tutorial.math.lamar.edu/pdf/Calculus_Cheat_Sheet_Integrals.pdf

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