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Mathematics
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Divide.
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the x^2 - 4 can be written as (x - 2)(x + 2) and then solve
how @miteshchvm
\[\frac{ \frac{ (x-2)(x+2) }{ x-8 } }{ x-2 }\]
\[\frac{ (x-2)(x+2) }{ (x-8) } \div (x-2)\] \[\frac{ (x-2)(x+2) }{ (x-8) } \times \frac{ 1 }{ (x-2) } \] can you solve further?
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I wish I knew how to solve it
you can eliminate x-2 bcoz x-2/x-2 = 1 hence the answer would be x+2/x-8
or you can write the answer as \[\frac{ x^2-4 }{ x^2 - 10x + 16 }\]
@miteshchvm so which answer would it be?
both are the same answers
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it depends on what the options are
I just listed my options
your options ae in other variables and the question is in other.
Your Right :) thanks alot :)
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