Car A and Car B leave from the same point at the same, with Car A traveling north and Car B traveling east. Car B is driving 10 miles per hour faster than Car A. If the two cars are 100 miles apart from each other after 2 hours of driving, how fast is each car driving?

Question

eyust707 · Answer

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$y = V_{y} t$
$x = V_{x} t$
$V_{x} = V_{y} + 10$
Substituting $V_{x}$ in to the second equation we get
$x = V_{y}t + 10t$
Then we put those x and y equations into the distance formula posted in the picture
$D.A. = \sqrt{(V_{y}t + 10t)^2+(V_{y} t)^2}$
We know that $t = 2$ when $D.A. = 100$
Just plug those values in and solve for $V_{y}$
With that you can find $V_{x}$

anonymous · Answer

=p is there a simpler way? I have no idea what all that means.