Question

The force F1, 10.0N acts at 10.0cm. What is the magnitude of the torque due to F1 about an axis through Point A perpendicular to the page? Is it clockwise,or is it counterclockwise? ( Point A is at 0 on a meter stick. There is also a point B at 50cm and F2 is 70cm with a force of 15.0N)

Answer 1

what's the angle of F1 to the meter stick?

Answer 2

no angle is given

Answer 3

so does it look like that?

Answer 4

yes

Answer 5

that's 90 degrees

torque = F*r*sin(90)

Answer 6

=10N*.1m*1 = 1Nm

Answer 7

direction of torque would be into the screen (clockwise rotation)

Answer 8

questions?

Answer 9

what is the r? Is that the 10cm?

Answer 10

yes

Answer 11

Hi @Algebraic! your ava's still gloomy as usual.

Answer 12

sad, not gloomy.

Answer 13

b/c math is hard :(

Answer 14

torque = rF
= 0.1(10)
=1 Nm