Question

Given two similar triangles one of which has twice the perimeter of the other , by what factor is the area of the larger triangle bigger than the smaller?

Answer 1

options are

a) 2

b) 4

c) \[\sqrt{2}\]

d) \[2\sqrt{2}\]

Answer 2

@UnkleRhaukus @goformit100 @Gowthaman @Algebraic! @zzr0ck3r
@Callisto @Hero

Answer 3

@bmp @robtobey @experimentX @eyust707

Answer 4

you do not need the help of eleven people for this question

Answer 5

hey!! i need .... also you

Answer 6

ok sry......... @UnkleRhaukus

Answer 7

plz solve my problem

Answer 8

It is a) 2

Answer 9

The area of a triangle is its base times its high, we need to know how much these values change when you change the perimeter.
In terms of these quantities the perimeter is: base+high/cos t+high/cos u, if it is twice the perimeter, then 2base+2high/cos t + 2high/cos u, so the change in sizes is proportional. So you can use the same factor of that you increase the perimeter to increase the hight and base, so it gets 2base*2hight=4*area, so the answer is 4.

Answer 10

no @Gowthaman

Answer 11

I dont know if I explained it well, and now I'm thinking and I could have just given you a lead and helped you solve it, sorry, I'm new at this..

Answer 12

the arearea of a triangle is actually 1/2 the base times its height

Answer 13

area* .....try it with that and see how it works

Answer 14

@ivanmlerner @Mpost1994 right area of triangle is 1/2 the base times the height

Answer 15

thats ...what..i ...just said ._.

Answer 16

but the answer is right

Answer 17

or any method

Answer 18

Yeah, thats right sorry, but the method is still valid though.

Answer 19

hey!!! i don't know very much trignometry.....

Answer 20

blocked

Answer 21

I know it^

Answer 22

what! blocked? @Algebraic!

Answer 23

plz be fast @goformit100

Answer 24

But that is just a detail, you can think it by logic also, that when the perimeter is doubled, the sides mantain its proportions.