Solve the system using the substitution method. If there is no solution, state so. Can someone please help me to understand how to do this? y=2x+5 x+y=2
where is equation
Sure but I need an example to help work with. Do you have one?
I have one hold on.
y=2x+5,so x+2x+5=2,now solve
y=2x+5 and x+y=2
OH this is fine Now to substitute means to replace one thing with an another...So what are we substituting.? Well that would be an amount for a variable. To solve an equation you can really only have one variable. y=2x +5 right? ...so replace y with 2x +5 in the other equation so you have only one variable. x + 2x + 5 = 2 3x + 5 = 2 Subtract 5 and you get -3 3x = -3 Now divide by 3 and you get x = -1 Sorry it was so many lines..but i hope this helps
oh ok @Mpost1994 @roshan2004 Now I see what I was doing wrong I was trying to solve for x but didn't know I could also use y to try and solve the problem explains why it was working lol This is so confusing!
How do you know which variable to use?
You can use any variable you like, you will get the same answer, Don't worry !!!, that's the beauty of equation :-)
You can use any variable you like.. but most of the time it will be obvious which one to use...for example I knew to use y this time because it told me exactly what y = in terms of x that is ..what y equals using only numbers and the x variable. Do you get it? :)
Yes but is this a solution? @Mpost1994 @roshan2004 Because on my hw I am suppose to write either solution-independent no solution-parallel or same line infinitely many dependent how do I know which one to put for this system?
Or how can I determine the answer?
Can you give me the choices seperately again?
A. solution-independent B. no solution-parallel C. same line infinitely many dependent
A
Don't you need to solve for y roshan?
@roshan2004 Why A? How did you get that? Can you please explain?
If it's a solution wouldn't there be and x and y-intercepts?
Look at this site and maybe this will explain...alright? http://www.algebra.com/algebra/homework/coordinate/Types-of-systems-inconsistent-dependent-independent.lesson Pm after you read this okay?
Here's an example I have that the professor did on the board: Solve by substitution : 3x+y=-1 x+2y=8 1. x+2y=8 -2y -2y x=-2y+8 2. 3(-2y+8)+y=-1 -6y+24+y=-1 -5y+24=-1 -24 -24 -5y=-25 / -5 y=5 3. 3x+5=-1 -5 -5 3x=-6 x=-2
So solution is (-2,5) Independent But idk how he did this?
Oh well that would what we already did .....just solve for both variables using both equations
y= -x+2 y= 2x + 5 Put those into a graph and solve for the solution ..which is where the lines cross
so y=3?
@Mpost1994
Yes :) -(-1) +2 or 2(-1) +5 both come out to 3 ^.^
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