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OpenStudy (anonymous):
A fish tank initially has 4kg of salt dissolved in 100L of water.
OpenStudy (anonymous):
It is decided that this concentration is too high! So, fresh water is mixed at a rate of 10L/mind, while 10L of mixture is removed per minute.
OpenStudy (anonymous):
If x kg/L is the concentration of the saltwater solution in the tank t seconds after the fresh water is first added, find the differential equation for x.
OpenStudy (anonymous):
I thought dx/dt = -10x
OpenStudy (anonymous):
But i got the answer wrong
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OpenStudy (anonymous):
water remains constant at 100L. Only salt concentration changing with time
OpenStudy (anonymous):
Yep
OpenStudy (anonymous):
So concentration = 100x?
OpenStudy (anonymous):
i think it will be dx/dt = 4 - 0.4t
OpenStudy (anonymous):
sorry 100 dx/dt = 4 - 0.4t
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OpenStudy (anonymous):
I got the solution, it says 10dx/dt + x = 0
OpenStudy (anonymous):
But i dont know how they got that
OpenStudy (anonymous):
maybe it's like this : salt concentration is being reduced by 10 X / 100 L where x is salt concentration and water remains constant so only changing thing is 10 L of solution being removed