Find the distance between (–2, –3) and (–6, –12). Round the answer to the nearest hundredth, if necessary. a. 9.85 units c. 13 units b. 7.26 units d. 17.49 units
Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\) does this help ??
omg do you have that pre-copied or something lol no way you typed it that fast
@Mew did u get you r distance ?
do you know what to do?
@Mew i assume you are trying ..... are u stuck ?
I'm trying. My teacher is lecturing so I can't use the computer when he is.
I only have a crappy calculator to use. :I
-2-(-6)=?
theres a way to see if you can do this with as minimal calculations as possible
subtract one point from the other (–2, –3) and (–6, –12) +6+12 +6+12 ------- ------- 4 , 9 0 , 0 this, in effect, moves it to the origin so that you can read off the leg values |dw:1349179044415:dw|
now, by properties of right triangles; the length of the missing side is longer than the logest leg; but shorter than the sum of the legs are there any values bigger than 9 but less than 9+4
Ah, thank you. :) Much easier.
as long as only one of the choices fits, that is a pretty simple way to go; and its a good way to narrow down the field :) youre welocme
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