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Mathematics 17 Online
OpenStudy (anonymous):

Three consecutive vertices of a parallelogram are points (2, 4), (0, 0), and (6, 0). The fourth vertex is point

OpenStudy (anonymous):

Draw the figure and mark the coordinates first

OpenStudy (anonymous):

then...Diagonals of parallelogram bisect each other....then use section formula

OpenStudy (anonymous):

Try it out..)

OpenStudy (anonymous):

Not enough information. There is more than one solution.

OpenStudy (anonymous):

(8,4)

OpenStudy (anonymous):

Simply observe the given, it's a parallelogram and so, the opposite sides must be parallel to each other.

OpenStudy (anonymous):

There are two other possible solutions. @Jeffrey_Calderon

OpenStudy (anonymous):

I don't think so. Then give me the other solution.

OpenStudy (anonymous):

Without a restriction on which quadrant the fourth point must be in, it can be in any of three locations.

OpenStudy (anonymous):

Dude, take note of the word "parallelogram"

OpenStudy (anonymous):

|dw:1349187485045:dw|

OpenStudy (anonymous):

Do you see the three parallelograms (excuse the sloppy drawing)

OpenStudy (anonymous):

|dw:1349187627457:dw|

OpenStudy (anonymous):

You can compute all the slopes yourself and prove that the lines are parallel. And you can also verify using distance formula, if you like, that opposite sides are congruent.

OpenStudy (anonymous):

Oh. yes @CliffSedge, you are right. did't thought about that. Sorry. :) Maybe, there are four answers to the problem.

OpenStudy (anonymous):

There are three solutions. There might be a fourth, but I wouldn't know how to find it. Usually these sorts of problems will be stated such that 'the fourth point is in the fourth quadrant' or something like that.

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