Question

Another question--similar. I did try, but couldn't get it right for some reason.

Answer 1

what did you do ?

Answer 2

what is 11/33 = ?

Answer 3

\(\huge \frac{a^m}{a^n}=a^{m-n}\)

Answer 4

keep it as 1/3

Answer 5

\(\huge \frac{d^2}{d^4}=d^{2-4}\)
when division, you subtract the exponents

Answer 6

then what will be e^5/e^2 ?

Answer 7

that is correct!

Answer 8

e^5/e^2 = e^{5-2} = e^3

Answer 9

and the exponent of d u got ?

Answer 10

yup, but thats in denominator.
now there is ^2 overall, so just double all the exponents, what u get?

Answer 11

yes double.
3*2 = 6 and not 9
so u get e^6
d^4
and whats the square of (1/3) ?

Answer 12

no, square
(1/3)(1/3)=?

Answer 13

yup, 9 in denominator.
so which option is it ?

Answer 14

yup

Answer 15

sure

Answer 16

it becomes

\[\frac{ (-4)^3(x^2)^3 }{ x^3(z^2)^3 }\]

Answer 17

what will you get then ?

Answer 18

first you forgot z..
the second thing is that at the numerator you got (x^2)^3 which is x^(2*3)
in the denominator you got only x^3

Answer 19

so you meant to write on the denominator z^6 instead of x^6 ..
you just wrote it wrong
but if thats what you meant so it is correct
\[\frac{ -64x^3 }{ z^6 }\]

Answer 20

:)