Having trouble understand this concept. Can someone help? Is the following always, sometimes, or never true? 6 + 8x – 9 = 11x + 14 – 3x (1 point) always true sometimes true never true

Question

Having trouble understand this concept. Can someone help? Is the following always, sometimes, or never true?  6 + 8x – 9 = 11x + 14 – 3x  (1 point) always true sometimes true never true

anonymous · Answer

collect terms on the right and on the left. 
if they are identical, then it is always true

they are not identical in this case however

anonymous · Answer

when you collect terms on the left you have $8x-3$ because $6-9=-3$
when you collect terms on the right you have $8x+14$ because $11x-3x=8x$

anonymous · Answer

so now you are looking at $$8x-3=8x+14$$ and then the question is, since they are not identical, is it not "always true" so the question is, is it 'sometimes true" or "never true"?

you see  you have the same number of $x$'s on both sides, namely 8 of them. 
whatever $x$ is on the left, it must be the same number on the right, so the $8x$ on the left is identical to the $8x$  on the right

but the numbers are different
therefore it is never true, because you cannot subtract 3 from a number and get the same answer if you add 14  to the same number!

anonymous · Answer

if you had $8x-3=7x+14$ then it would be "sometimes true" because you  have a different number of $x$'s on the left and the right