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Determine algebraically whether the function is even, odd, or neither even nor odd. Odd Even Neither
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function is \[f(x)=x+\frac{ 12 }{ x }\]
Find f(-x) by replacing x in f(x) by -x. If f(-x) = f(x), then the function is even If f(-x) = -f(x), then the function is odd else neither.
\[f(-x)=-x-\frac{12}{x}=-(x+\frac{12}{x})=-f(x)\]
so is an odd function?
yes it is
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how about \[f(x)=x+x^2\]
thanks
no problem :)
neither?
yes
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yey!! thank you
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