Need help solveing the inequality 4xy-3y^2>=0
Hum, u have y(4x-3y) >=0 so seems you have cases...
definitely cases. have two unknowns
y>0 and y < 0 (y=0 as well...)
are you solving for \(x\) in terms of \(y\)? because from what @estudier wrote, you see if \(y>0\) you need \(4x-3y>0\) making \(x>\frac{3}{4}y\) whereas if \(y<0\) it is the opposite
Well i have just so far come to the conclution that x>= 3y/4 , y>=0 or x<=3y/4 ,y<=0
Oh god why not i just write the full question i have been given: Determination of the domain and outline of the domain in an xy chart for the function f(x,y)=sqrt(4xy-3y^2)
Yes, one is sort of reverse of the other....
That should be a surface of some sort, hyperbolic maybe...
http://www.wolframalpha.com/input/?i=f%28x%2Cy%29+%3Dsqrt%284xy-3y^2%29 is what it looks like
An infinite elliptic cone, lol
But should it not be 2 dimensional when it is a xy-diagram?
It is 2 dimensional, a surface...
Not to mix up the dimensionality of the object and the space it is embedded in....
U understand, right? f(x,y) is a function of 2 variables, so a surface...
You may think of f(x,y) = z
Yea beside i perhaps not made it clear that i am going to make a xy-diagram of the domain. i understand your point if you plot f(x,y), but that is not what i am going to find i think.
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