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y=arctan(x-sqrt(1+x^2))
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what u want done?
\[\frac{ 1 }{ 1+(x-\sqrt{1+x^2)} }(1-\frac{ 1 }{ 2 }(1+x^2)^{-1/2})(2x)\]
oh differentiate
am I on the right track?
oh (x-sqrt(1+x^2))^2
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that first term is squared on the bottom
yep... you're on the right track...
ok great, i will simplify
\(\Large [arctan(f(x))]'=\frac{f'(x)}{1+[f(x)]^2} \)
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