Question

Solve the equation. Identify any extraneous solutions.

Answer 1

A. 0 and 7 are solutions of the original equation.
B. 0 is a solution of the original equation. 7 is an extraneous solution.
C. 7 is a solution of the original equation. 0 is an extraneous solution.
D. –7 is a solution of the original equation. 0 is an extraneous solution.

Answer 2

is the answer A?

Answer 3

@campbell_st can you help?

Answer 4

is your image the equation or a solution?

Answer 5

@campbell_st the first image is the question

Answer 6

ok.. so its

\[\frac{2\sqrt{5} - 2}{\sqrt{5}} = 1.1\]

just checking, is that the question?

Answer 7

No sorry! it should of been

Answer 8

ok... so looking at the question I'll assume you are working in real numbers so

\[w \ge 0\]

but it is simply a case of squaring both sides...

\[w^2 = 7w\]

does that make sense

Answer 9

yes

Answer 10

ok... then your equation can be written as

\[w^2 - 7w = 0\]

which can be factored...

Answer 11

7w?

Answer 12

nope whats the common factor

\[w(w - 7) = 0\]

now find the values of w that make the equation true.... what are the solutions...

Answer 13

i dont know how to find the answer

Answer 14

ok...what values can w take so that

w(w - 7) = 0

its simply w = 0 or w = 7

why

0(0 - 7) = 0

and

7( 7 - 7) = 0

thats the solution.

Answer 15

Oh I see so the answer is B?

Answer 16

the solutions are w = 0 and 7 you can decide on the extraneous

Answer 17

how can i find what number is the extraneous

Answer 18

to check if a solution is extraneous, don't you substitute into the original equation to see if its true

Answer 19

I do not really know :(

Answer 20

there are no extraneous solutions

Answer 21

so its A? LIke a thought?

Answer 22

it is....