A sample of gas occupies a volume of 482 mL at a temperature of 282 K. At what temperature will this sample of gas occupy a volume of 502 mL? Show all of the work used to solve this problem.

Question

anonymous · Answer

I will assume that the gas is at constant pressure, since it is not mentioned at all. 

Using PV = nRT and the face that the pressure is a constant, we see that the Volume and the Temperature (in Kelvins) are directly proportional to each other. So, when the volume is increased by a factor of 502/482, the temperature (in Kelvins) is increased by a factor of 502/482. Therefore, the new Temperature is: $$ (282 \, \text{K}) \cdot \dfrac {502}{482} = \boxed {294 \, \text{K}}. $$