Question

Find crititcal numbers of the funtion

Answer 1

\[\frac{ y-1 }{ y^2-y+1 }\]

Answer 2

So what constitutes a critical number? Do you know how to find them? ^^

Answer 3

\[\frac{ (y^2-1+1)(1)-(y-1)(2y-1) }{ (y^2-y+1)^2 }\]

Answer 4

upper left part, y^2-y+1 :O not y+2-1+1

Answer 5

Rest of it looks good though c:

Answer 6

oh ya

Answer 7

So simplify that beast down c: then what next c: hmmm

Answer 8

Simplify the top i mean * c:

Answer 9

\[\frac{ -y^2+2y }{ (y^2-y+1)^2 }\]

Answer 10

Hmm looks good c:
So critical points!!
You confused about what to do next? :D

Answer 11

well, should i simplify the bottom?

Answer 12

or just set the top = 0

Answer 13

y(y-2)=0

Answer 14

Just top = 0 :D
You're technically setting the entire thing equal to 0, but you just multiply through by the denominator and it goes away :)

Answer 15

y=0, y =2

Answer 16

=D

Answer 17

thanks @zepdrix !!!!!!!!! :P

Answer 18

OO gj :D im not even sure why you posted this question XD you just breezed through it! hah

Answer 19

lol!!!