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Mathematics 12 Online
OpenStudy (mariebrittany07):

4p+2=3p-7

OpenStudy (anonymous):

can you please show me what you have done or what you intend to do?

OpenStudy (carson889):

p = -9

OpenStudy (anonymous):

4p-3p=-7-2 p=-9

OpenStudy (mariebrittany07):

Can you please show me how you figured it out please

OpenStudy (mariebrittany07):

I am still learning algebra 1

OpenStudy (mariebrittany07):

I just started algebra 1 this year and i am trying to understand the algebra but it is so hard to figure out

OpenStudy (carson889):

It all stems from the idea that what you do to one side of the equation you must do to the other. The idea is to isolate the variable, what that means is we want to have the variable (in this case it is p) on one side and a constant (number) on the other side. If we look at the equation we can isolate p to the left side (it doesn't matter which side you choose) by subtracting 3p from the right side. And as we know anything you do to the right side must be done to the left. Thus 4p+2=3p-7 now becomes 4p - 3p + 2 = 3p -3p -7. When we do simple subtration: 4p - 3p we get 1p (we can write this as just p instead of 1p), and on the right side 3p -3p = 0. Now our equation looks like this p + 2 = -7. We are closer now but we still need to get rid of the 2 on the left hand side of the equation. Similar to what we did previously, we get the 2 of the left side by subtracting it. Again as we should know, we now also need to do this to the right hand side. So p + 2 - 2 = -7 - 2. Do your simple subtraction and Voila! 2 -2 = 0 and -7 - 2 = -9. Therefore p + 0 = -9, and because zero is zero it doesn't matter so we can write the final equation as just p = -9

OpenStudy (mariebrittany07):

but p is 4 and 3 why two different numbers

OpenStudy (mariebrittany07):

are you still there

OpenStudy (carson889):

Sorry. The 4 and 3 are just constants, the p is a variable. We can imagine a variable as a number which we may not have yet assigned an actual value. The value of p remains the same and thus is equal to any other p variable. In this case we are shown 4p and 3p. For example if we knew somehow that the variable p was equal to 6, then 4p, which really just means 4 multiplied by p, would equal 6*4 = 24. Basically there are not two different p's, the p's are equal and thus we are allowed to subtract, add, divide, multiply them. If I gave you the question: what is 4p-3p? Imagine, p stood for bananas or chocolate bars. Then the equation would read what is 4 chocolate bars minus 3 chocolate bars? Well... knowing how to subtract, I would respond 1 chocolate bar. In the case of 4p -3p, the result is 1p.

OpenStudy (carson889):

A further proof: Say hypothetically p = 6. 4p - 3p = 4*6 - 3*6 (factor out the 6 because it is common to both numbers) = 6*( 4 - 3 ) = 6*(1) = p*(1) = p Just the same if we don't know what p equals. 4p - 3p = 4*p - 3*p (we can factor out the 'p' because it is common to both numbers) = p*(4 - 3) I know p * (4-3) is right because if we multiply p by 4 and subtract p multiplied by 3 we again get 4*p - 3*p, which as you can see is what we started with. The 4 - 3 inside the brackets = 1, thus: = p*(1), one times any number is equal to that number ex: 1*5=5, 1*203 = 203 = p

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