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Mathematics 16 Online
OpenStudy (anonymous):

Help please? Question in reply. I don't understand the question well.

OpenStudy (anonymous):

http://s12.postimage.org/cwim9sm6j/Problem.png

OpenStudy (anonymous):

a is the inverse of f. f^-1(x) <--switch the places of x to y and y to x. f'(x) is the first derivative. f'(c) is the first derivative using the value of c.

OpenStudy (anonymous):

oh haha. (f^-1)' (c) ... i guess this is the inverse then the first derivative of f(x). tricky.

OpenStudy (anonymous):

xD

OpenStudy (anonymous):

so...i guess...you have to get the inverse first and THEN derivative.

OpenStudy (anonymous):

because the first question asks for a first.

OpenStudy (anonymous):

Hmm I'm trying to do the first one, I'm kind of stuck on finding the inverse. Y = 4x + 6x^(7) X = 4y + 6y^(7) What do you do next? I know you can take out a 2y from the right side, but then what?

OpenStudy (anonymous):

excellent question. haha. you could do that but that would leave you with a y on the other side. my guess would be to ^7 the 4y. besides that i dunno sorry.

OpenStudy (anonymous):

Let me check what theorem '6.5' is lol.

OpenStudy (anonymous):

It's saying to do what we just did... Set equation equal to y. Solve for X. Interechange X and y.

OpenStudy (anonymous):

yes thats what you did and you got stuck with X = 4y + 6y^(7) now you have to isolate y. if you did isolate y in that state, you would get a y in the other side of the equation. i guess that would be fine because you would derive it. if you derive it you would get y'. then you can probably isolate y' so... y' = (fraction) + c ....maybe?

OpenStudy (anonymous):

Hmm I just found this. It might help. The formula is: 1/f'(f^(-1(c))

OpenStudy (anonymous):

1/f'(f^(-1)(c))

OpenStudy (anonymous):

that, sorry.

OpenStudy (anonymous):

so...a function within a function. how would you use that? i havent seen that before.

OpenStudy (anonymous):

Hmm I got the first answer, kind of. You can do it by inspection. What do you plugin that gives you 10? 4(1) + 6(1)^(7) = 10 :D

OpenStudy (anonymous):

I made a mistake. They want -10.

OpenStudy (anonymous):

It's -1.

OpenStudy (anonymous):

sorry i cant help.

OpenStudy (anonymous):

It's a weird problem, really.

OpenStudy (anonymous):

haha it is. who would think about getting the inverse and then the derivative of a function? maybe for higher college, it could happen.

OpenStudy (anonymous):

I got the 4 answers, finally xD.

OpenStudy (anonymous):

4x + 6x^(7), they want c = -10. So 4(-1) + 6(-1)^(7) = -10. a = -1. So then, take the derivative of 4x + 6x^(7). 4 + 42x^(6), plug -1 in. You get 46. Using that formula, 46 goes on the bottom. Answer for second question is 1/46.

OpenStudy (anonymous):

Same thing for the other one, they want 14. Plug 9 in, you get 14. A = 9. Take the derivative of the equation, u get 2x -13, plug 9 in, you get 5. Using the formula, you get 1/5.

OpenStudy (anonymous):

haha. nice. then you got it.

OpenStudy (anonymous):

The question wasn't explained well lol. Thanks :D

OpenStudy (anonymous):

haha. i didnt really do anything. you did it. Good job.

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