Question

x^4-10x^2-8=0
solve for x

Answer 1

solve
\[x^2-10x-8=0\] and then replace \(x\) by \(x^2\)

Answer 2

yuch, this is ugly
did you get the solutions?

Answer 3

no i am still trying

Answer 4

about to use quadratic

Answer 5

i cant get it

Answer 6

easiest is quadratic i guess
\[x={-b \pm \sqrt{b^2-4ac}\over 2a}\] \[x={10 \pm \sqrt{(-10)^2-4(1)(-8)}\over 2(1)}\]\[x={10\pm\sqrt{100-(-32)}\over2}\]\[x={10\pm\sqrt{132}\over2}\]so in simplest ways you could say:\[x=5+{\sqrt{132}\over2}~~~~~~~~~or~~~~~~~~~~x=5-{\sqrt{132}\over2}\]