Find the vertex for the parabola whose equation is y= 3x^2 - 6x +5
The formula for finding the x value of the vertex is -b/(2a). Once you find the x value, you can plug it into the equation to find the y value.
I understand the process but for some reason I have had great difficulty for this problem. Would you mind going through it with me step by step? Would be much appreciated.
Sure. So the first step is to find the x value. The formula is -b/2a. By using this model, \[ax ^{2}+bx+c\], can you identify what "b" is?
in this case b is -6
Right, but you need b to be negative. So you will do 6/2a. In this case, a is 3. So 6/(2*3) equals what?
1, I thought you had to use the method of completing the square. If this works that is much better lol
Haha you can use this. 1 is correct. Now all you have to do is plug in 1 for x to find your y-value. :)
Thank you so much! Could you by any chance show me where I was going wrong when I was trying to complete the square to solve it? I started off by dividing the b value by two than squaring it. that new value replaced the c value and the previous c value was subtracted by the new c value. So I ended up with (3x^2-6x+9) - 4. from there I tried to pull out the three but thats where I ran into trouble.
To be honest, completing the square is not my forte. Lol, I am not the right person to ask. But I'm glad I could help!
Well thanks anyways!
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