Solve the system by graphing 3x=y+3 6x-3=2y
hi, i just learned systems of equations today in class. i really like them :D so, the first thing you have to do is to get these equations into y=mx+b form. then, plot the y intercept onto the graph. use the slope to find the direction of the lines. and there, you have graphed them. do you need to find a solution, too?
do you understand?
No i am so confused. i need to know the points to plot.
ok, do you know how to put these equations in y=mx+b form?
yea y=3x+3
y=-3x+3 because we subtract.
how about the other equation?
2y=6x-3
simplify it further, you need to get the y by itself.
divide by 2 right?
yes
y=3x-3/2
?
yes. good. ok so we now know the y intercept and slopes for bothe equations
both*
do you know them?
-3=m
would it be 3/1
for the second equation, the slope is 3, or 3/.
3/1* sorry.
what about the y intercepts now?
what is the first eqution then. I thought 3/1 was the first equation?
the first equation is y=-3x+3. so the slope is -3. the second equation is y=3x-3/2, so the slope is 3.
yea but the rise over run for the first is 3/1?
-3/1, you have to take the negative too.
ok?
Yes and then the other one is -3/2?
the second equation is y=3x-3/2, so the slope is 3.
-3/2 is the y intercept.
ok?
the number next to the x is the slope. the number being added/subtracted to it is the y intercept.
are you getting it? i can show you everything, if that would help.
What would the coordinate points
Woudl you be able to help me with another problem?
x-3y=-3 X=3y=9
the y intercept for the first equation is (0,3) the y intercept for the second equation is a little weird. -3/2 = -1 and 1/2. so you will plot (0,3) and (0, -1 half) always plot the y intercept first. ok? and yes I will try my best to help you with another problem :D
Ok thank you. We sent the message at the same time. The problem is x-3y=-3 3y=x-3
so far i have y=x/3-1
ok but do you have the first problem graphed?
nvm this is the problem x-3y=-3 x+3y=9
yes i did get it graphed
ok good. x-3y=-3 -3y=x-3 y=1/-3x+1 see what i did there?
yes i did!
I got the same answer!
awesome! can you write the correct equation for the second equation?
for x+3y=9
y=x/3-3
you're close! x/3 is hard to plot because we need to know the rise, and we cant plot the rise because x is just a variable. soo... x/3 = 1/3x now that's easier to work with. that is your slope.
-3 is my plot and 1/3 is the rise over run?
and... it is not -3, it is 3 because you divide 9 by 3 and that gives you 3.
oh ok
got it?
i always get my graphing wrong? I am doing it wrong somehow
plot 3 then move up one and to the right three points.
plot (0,3) i meant.
I am confused. so what do i plot first?
i plotted (1,0) then went up one and over -3
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