how do you put Y+3=-5/6(x-1) into standard form?
do you know what the standard form is? I would usually say it is y = mx + b, where m is the slope and b is the y intercept. However, if your class has said something different, we can use that...
they are using y=mx+b
good :) So you need to multiply out and simplify the equation they gave you: Y+3=-5/6(x-1) <<-- is the (x-1) in the denominator or numerator??
so...i got Y+3=-5/6X+5/6 WHATS THE NEXT STEP?
guess it was the numerator. So then subtract 3 from both sides to get y all alone on the left. y +3 -3 = -(5/6)x +(5/6) - 3 y = -(5/6)x +(5/6) - 3 Then get a common denominator and combine (5/6) and -3 and you will be done
Y=-5/6X-13/6.... AND THEN IM STUCK?
no, you are done :) That is the standard form: y = -(5/6)x - (13/6) is of the same form as... y = mx + b where m = -5/6 and b = -(13/6) That's all there is... you found the standard form :)
THATS ACTUALLY POINT SLOPE FORM. STANDARD FORM IS Ax+By=c and I dont know how to solve for that
sorry.:(
?????
ok... you are right, it is Ax+By=C no fractions, and A has to be positive.
I would clear the fractions first so that we just don't have to worry about that any more. Clear your fractions by multiplying by 6 on both sides.
I get\[6y+18=-5(x-1)\]Are you with me?
y=-5x-13?
I'm starting from what you wrote in your original post. y+3=(-5/6)(x-1)
ok
This is point-slope form. We need to get every variable over to the left with no fractions, in alphabetical order ( x then y ) and with no negative in front of the x term.
I want to get rid of the fraction first, so we can just forget about fractions.
ok but how did u get rid of the fractions on the right side
If the fraction involved has a 6 in the denominator, I can kill it by multiplying both sides by 6.
This uses the "balanced equation" concept to keep both sides equal... I multiply the right by 6 to kill the fraction. I multiply the left side by 6 to keep things balanced.
ok got it an then..
i get 6y+18=-5x+1
So the result should be 6y+18=(-5)(x-1)
You need to distribute that -5 to both terms inside the parenthesis.
6y+18=-5x+5
so for my answer i get 5x+6y=-19 is this right?
not quite...
:(
you have the x and y parts right
but if you distribute correctly... the number to use is... subtract 5 from both sides.
wait
???
I mean subtract 18 from both sides... der
so 5x+6y=-17
check that distribution step... 6y+18=-5(x-1) leads to 6y+18=-5x+5
then move the x term 5x+6y+18=5
then subtract 18 from both sides 5x+6y=5-18
5-18=?
-13
yes!
so... 5x+6y=-13
that is standard form
thank you soo much:)
You're welcome! :)
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