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what is the limit of h/tan(h) as h approches 0?
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write tan h as sin x / cos x
\[\frac{ h }{ \frac{ \sinh }{ \cosh } }\]
write that as cos x /(sin x/x) did u understand how ?
wouldn't it be \[\frac{ hcos(h) }{ \sin(h) }\]
oops, sorry i used x instead. yes, and u can bring that h in denominator of sin h to get cos h/(sin h/h) ok ?
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how could I bring the h to the denominator?
divide h in numerator and denominator
the answer is 1. how would i get that?
put h=0 in cos h (cos 0 = ?) use the standard limit sin x/x = 1 for denominator
ok thanks
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welcome ^_^ i hope u understand all steps.
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