The maximum value of the function

Question

hartnn · Answer

can be found by taking the derivative of that funtion and equating it to 0.

anonymous · Answer

y=$$\sqrt{2-x}$$

hartnn · Answer

so did u find y' ?

anonymous · Answer

y=-4[\sqrt{2-x}\]

hartnn · Answer

could u differentiate y ?

anonymous · Answer

differentiate the function, then put the differentiated equation = 0
you will have either one answer or 2,
if you get two answers, the one which has negative value will be the maximum value of the function ;)

anonymous · Answer

is it the y value?

hartnn · Answer

have u learned to differentiate x^n ?

anonymous · Answer

y'= nx^n-1

hartnn · Answer

so couldn't u differentiate y=-4 sqrt(2-x)  ??

anonymous · Answer

does the max. value asked here is the x or the y value?

hartnn · Answer

y value

anonymous · Answer

y'= 2/(2-x)^-(1/2)

anonymous · Answer

@dan18 , the correct way is to differentiate and equate to zero , but just by looking at this question once can tell it's maximum value is infinity for x=-infinity....pretty weird question i guess...are u sure u hv typed the question correctly

hartnn · Answer

wouldn't it be y'= 2/((2-x)^(1/2))

anonymous · Answer

I get x=2 @ y', then subts. it to the eq. does the max. value = 0?

anonymous · Answer

@dan18 is the question correct ?

hartnn · Answer

but actual answer is infact Max. value = 0 when x=2 http://www.wolframalpha.com/input/?i=y%3D-4+sqrt%282-x%29

anonymous · Answer

$$y=-4\sqrt{2-x}$$

anonymous · Answer

thak you guys!

anonymous · Answer

now u hv got the correct question, yes the max would be zero