Question

the roots of the quadratic equation 4x^2-(5a+1)x+5a=0 are p & q. if q=1+p,calculate the possible values of a,p& q.

Answer 1

Similarly we can find a relation for ur eqn.
\[4x^2-(5a+1)x+5a=0\]
\[4(x^2-\frac{(5a+1)}{4}x+\frac{5a}{4})=0\]
\[p+q=\frac{(5a+1)}{4}\]
\[p+1+p=\frac{(5a+1)}{4}\]
\[2p+1=\frac{(5a+1)}{4}-(1)\]
\[4(2p+1)=5a+1\]
\[pq=\frac{5a}{4}\]
\[p(1+p)=\frac{5a}{4}\]
\[4p(1+p)=5a-(2)\]
Using equations (1) and (2) find p and a.
Can u do it @wwe123?