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Mathematics 19 Online
OpenStudy (anonymous):

A weak acid H-A was dissolved in water providing a one molar solution of HA. The [H+] was determined to be 3.0*10^-5 at equilibrium. What is the pKa of HA?

OpenStudy (anonymous):

10 - log (9)

OpenStudy (anonymous):

Can I ask how you got to this answer. Isn't the equation of use pKa = -log[H+]? However, using this equation, I was never given the right answer which explains the question.

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