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Mathematics 7 Online
OpenStudy (anonymous):

Question ! Screenshot attached, question answered--need someone to see if I'm right.

OpenStudy (anonymous):

OpenStudy (anonymous):

it isnt right

OpenStudy (anonymous):

\[(\frac{ a }{ b })^{-2} = (\frac{ b }{ a })^{2}\]

OpenStudy (anonymous):

looks like you used it but you didnt raise the terms to the powers right

OpenStudy (anonymous):

\[(\frac{ abc^4 }{ 6a^{-2}b^3 })^{-2} = (\frac{ 6a^{-2}b^3 }{ abc^4 })^2\]

OpenStudy (anonymous):

no you have to raise to the power each term inside the ( ) \[(\frac{ 6a^{-2}b^3 }{ abc^4 })^2 = \frac{ 6^2a^{-2*2}b^{3*2} }{ a^2b^2c^{4*2} }\]

OpenStudy (anonymous):

does this help ?

OpenStudy (anonymous):

Why does such a simple equation have to be sooo long...:(

OpenStudy (anonymous):

lol no worries.. once you will get it it will be simple just some basic rules to follow

OpenStudy (anonymous):

so what is the answer ?

OpenStudy (anonymous):

umm..|dw:1349279819082:dw|

OpenStudy (anonymous):

check the answer once again

OpenStudy (anonymous):

a little fix you have to do there ..

OpenStudy (anonymous):

okay..well...okay..hold on.

OpenStudy (anonymous):

|dw:1349280038755:dw|

OpenStudy (anonymous):

yes thats right

OpenStudy (anonymous):

Thanks Coolsector :)

OpenStudy (anonymous):

yw :)

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