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OpenStudy (anonymous):
Question ! Screenshot attached, question answered--need someone to see if I'm right.
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OpenStudy (anonymous):
OpenStudy (anonymous):
it isnt right
OpenStudy (anonymous):
\[(\frac{ a }{ b })^{-2} = (\frac{ b }{ a })^{2}\]
OpenStudy (anonymous):
looks like you used it but you didnt raise the terms to the powers right
OpenStudy (anonymous):
\[(\frac{ abc^4 }{ 6a^{-2}b^3 })^{-2} = (\frac{ 6a^{-2}b^3 }{ abc^4 })^2\]
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OpenStudy (anonymous):
no you have to raise to the power each term inside the ( )
\[(\frac{ 6a^{-2}b^3 }{ abc^4 })^2 = \frac{ 6^2a^{-2*2}b^{3*2} }{ a^2b^2c^{4*2} }\]
OpenStudy (anonymous):
does this help ?
OpenStudy (anonymous):
Why does such a simple equation have to be sooo long...:(
OpenStudy (anonymous):
lol no worries.. once you will get it it will be simple
just some basic rules to follow
OpenStudy (anonymous):
so what is the answer ?
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OpenStudy (anonymous):
umm..|dw:1349279819082:dw|
OpenStudy (anonymous):
check the answer once again
OpenStudy (anonymous):
a little fix you have to do there ..
OpenStudy (anonymous):
okay..well...okay..hold on.
OpenStudy (anonymous):
|dw:1349280038755:dw|
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OpenStudy (anonymous):
yes thats right
OpenStudy (anonymous):
Thanks Coolsector :)
OpenStudy (anonymous):
yw :)
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