Question

the sum of the digits of a two digit number is 8.if 36 is added to the number,the digits interchange their places.find the number..

Answer 1

help me guysssss

Answer 2

Let n=a10+b. then a+b=8.

Answer 3

n+36=b10+a

Answer 4

dis is d second step???????

Answer 5

i think u can work from here on your own.

Answer 6

since u have two variables (the two digits) u must try to obtain two equations.

Answer 7

well n=a10+b and
n=b10+a-36

Answer 8

so a10+b=b10+a-36 so
\[ \large -9a-9b=-36 \]

Answer 9

therefore youu have the system
\[ \large \begin{cases}
a+b=8\\ -9a-9b=-36
\end{cases} \]

Answer 10

wait. there's something wrong. the system i wrote is inconsistent.

Answer 11

uff

Answer 12

no need i ll do it
thx for ur help anyway

Answer 13

9a-9b=-36

Answer 14

so a10+b=b10+a-36 so
−9a−9b=−36<-----*
9a-9b=-36

Answer 15

hmmk

Answer 16

u r right @hartnn

Answer 17

so we have the system
\[ \large \begin{cases}
a+b=8\\ -9a+9b=36
\end{cases} \]

Answer 18

now it is consistent!!

Answer 19

solve this and u r done.

Answer 20

okkk thx guyssssssssssssssssssss

Answer 21

:)

Answer 22

u r welcome

Answer 23

thx @hartnn olsoooo thxxx

Answer 24

welcome ^_^