Mathematics
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OpenStudy (anonymous):
Anyone knows how to do this?? Separate 38 into two numbers such that three times the smaller is 16 less than twice the larger.
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hartnn (hartnn):
yup.
hartnn (hartnn):
let 38 be separated into x and 38-x
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
do we set them equal to each other?
hartnn (hartnn):
three times the smaller is 16 less than twice the larger.
so
3x+16 2(36-x)
got this ?
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OpenStudy (theeric):
Only if those two "numbers" are equal to each other! Otherwise, no!
hartnn (hartnn):
3x+16= 2(36-x)
OpenStudy (anonymous):
okay, then solve right?
hartnn (hartnn):
yup
hartnn (hartnn):
find x from there, u will get the smaller number
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OpenStudy (anonymous):
then substitute for the right, correct?
OpenStudy (anonymous):
larger*
hartnn (hartnn):
yes, but first tell me what did u get 'x' value.
OpenStudy (anonymous):
11.2
OpenStudy (anonymous):
is that correct?
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hartnn (hartnn):
yes, even i get 11.2, i wonder why is it not and integer,
anyways, find larger using 36-x= ?
OpenStudy (anonymous):
using 36? or 38?
hartnn (hartnn):
sorry 38
OpenStudy (anonymous):
its okay, but I got 26.8 for large
hartnn (hartnn):
ohh.thats why we didn't get an integer, its 38,
sorry my typing mistake
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OpenStudy (anonymous):
oh
hartnn (hartnn):
solve this :
3x+16= 2(38-x)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
i got 28 for large, 10 for small
hartnn (hartnn):
i got x=12, please verify the calculations.....
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OpenStudy (anonymous):
oh yeah, your're right
OpenStudy (anonymous):
the larger is 26
hartnn (hartnn):
thats correct :)
OpenStudy (anonymous):
thank you
hartnn (hartnn):
welcome ^_^