Let F:R^4->R^3 be the linear mapping defined by T(x,y,s,t)={x-y+s+t; x+2s-t; x+y+3s-3t} find the bases of the ker(F)
@TuringTest pls hlp
got yer matrix yet?
jah
row reduce...
jah,actualy i started by finding the image (im(F)) so that i knw the Dim(ker(F)) and i found that is 2 .then i dnt knw how to proceed
I actually don't know what the image is I only know my way of doing linear algebra because I am self-taught The way I do it is find the transformation matrix, then row-reduce represent the solution set as a vector(s) the span of that/those vectors is the nullspace/kernel
yah, u can show me the way you do it
I am exercising so I can't type it all out, but check out example 4 here: http://tutorial.math.lamar.edu/Classes/LinAlg/Subspaces.aspx (nullspace and kernel are the same thing)
eixsh im failing 2 understand it, i dnt knw hw 2 contruct a set for a kernel
I will answer this in about 1hr or so, okay sorry I'm a bit busy
ok,no problem
Join our real-time social learning platform and learn together with your friends!