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Mathematics 16 Online
OpenStudy (anonymous):

Let F:R^4->R^3 be the linear mapping defined by T(x,y,s,t)={x-y+s+t; x+2s-t; x+y+3s-3t} find the bases of the ker(F)

OpenStudy (anonymous):

@TuringTest pls hlp

OpenStudy (turingtest):

got yer matrix yet?

OpenStudy (anonymous):

jah

OpenStudy (turingtest):

row reduce...

OpenStudy (anonymous):

jah,actualy i started by finding the image (im(F)) so that i knw the Dim(ker(F)) and i found that is 2 .then i dnt knw how to proceed

OpenStudy (turingtest):

I actually don't know what the image is I only know my way of doing linear algebra because I am self-taught The way I do it is find the transformation matrix, then row-reduce represent the solution set as a vector(s) the span of that/those vectors is the nullspace/kernel

OpenStudy (anonymous):

yah, u can show me the way you do it

OpenStudy (turingtest):

I am exercising so I can't type it all out, but check out example 4 here: http://tutorial.math.lamar.edu/Classes/LinAlg/Subspaces.aspx (nullspace and kernel are the same thing)

OpenStudy (anonymous):

eixsh im failing 2 understand it, i dnt knw hw 2 contruct a set for a kernel

OpenStudy (turingtest):

I will answer this in about 1hr or so, okay sorry I'm a bit busy

OpenStudy (anonymous):

ok,no problem

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